t=36t-5t^2

Solution for t=36t-5t^2 equation:

t=36t-5t^2

We move all terms to the left:

t-(36t-5t^2)=0

We get rid of parentheses

5t^2-36t+t=0

We add all the numbers together, and all the variables

5t^2-35t=0

a = 5; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·5·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*5}=\frac{0}{10}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*5}=\frac{70}{10}
=7
$